Question

Divide 32 xy² - 16 x^2y by 16xy x+5/5 = 6x
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Answer 1

Answers

Given :

A number is divided into two parts such that one part is 15 more than the other if the two parts ratio 5:2

To find :

The numbers and the two parts

Solution :

A number is divided into two parts such that one part is 15 more than the other

$\\\blacktriangleright\tt{\purple{So, let\: the \: second \: part \: be \: x \: and \: the }}$$\tt{\purple{first \: part \: be \: x + 15}}$

$\\{\Large\ast} \: \underline\boldsymbol{\red{According\:to\: the \: Question}}\:{\Large\ast}$⠀

The two parts ratio is 5:2

$\\\implies\tt \dfrac{(x + 15)}{x} = \dfrac{5}{2}$

$\implies\tt 5x = 2(x + 15)$

$\implies\tt 5x = 2x + 30$

$\implies\tt 5x - 2x = 30$

$\implies\tt 3x = 30$

$\implies\tt x=\cancel\dfrac{30}{3}$

$\implies\tt x=10$

Second part = x = 10

First part = x + 15 = 10 + 15 = 25

${\underline{\boxed{\bf{\purple{Required\:number = First\:part + 2nd\:part}}}}}$

${\underline{\boxed{\bf{\purple{Required \: number = 10 + 25 = 35}}}}}$