Question

Divide 34 into two parts in such a way that 4/7 of one part equal to 2/5th of the other

Answer 1

let first part x and 2nd part 34 - x

a/c to question ,

4/7 (x ) = (34 - x )(2/5)

4x/7 + 2x/5 = 34 x 2/5 = 68/5

34x/35 = 68/5

x = 14

Answer 2

Answer:

34 is divided into two parts in such a way that

first part = 14

and

second part = 20

Explanation:

Given number = 34

Let 34 is divided into two parts

i.e

First part = x

Second part = (34-x)

According to the problem given,

$\frac{4}{7}\:of \: first \: part\\=\frac{2}{5} \: of\: second \: part$

$\implies \frac{4}{7}\times x = \frac{2}{5} \times (34-x)$

Do the cross multiplication, we get

$\implies 20x = 14(34-x)$

$\implies 10x = 7(34-x)$

$\implies 10x=7\times 34 -7x$

$\implies 10x+7x = 7\times 34$

$\implies 17x = 7\times34$

$\implies x = \frac{7\times 34}{17}$

After cancellation,we get

$\implies x = 14$

First part = x = 14

Second part = 34-x

= 34 - 14

= 20

Therefore,

34 is divided into two parts in such a way that

first part = 14

and

second part = 20

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