divide 3420 into two parts such that, one part is 28% more than one
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LET ONE NUMBER=x
i.e. THE OTHER NUMBER=x+28x/100
i.e. x+x+28x/100=3420
i.e. 228x=342000
i.e. x=342000/228=1500
AND THE SECOND NUMBER=1500+1500x28/100=1500+420=1920
i.e. THE OTHER NUMBER=x+28x/100
i.e. x+x+28x/100=3420
i.e. 228x=342000
i.e. x=342000/228=1500
AND THE SECOND NUMBER=1500+1500x28/100=1500+420=1920
bainadamsya:
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