Question

Divide: 35(y4-5y3-24y2)÷7y(y-8)​

Answer 1

Step-by-step explanation:

$35(y ^ { 4 } -5y ^ { 3 } -24y ^ { 2 } ) \div 7y(y-8) \\ \frac{35y^{4}-175y^{3}-840y^{2}}{7}y\left(y-8\right) \\ \frac{\left(35y^{4}-175y^{3}-840y^{2}\right)y}{7}\left(y-8\right) \\ \frac{\left(35y^{4}-175y^{3}-840y^{2}\right)y\left(y-8\right)}{7} \\ \frac{\left(35y^{5}-175y^{4}-840y^{3}\right)\left(y-8\right)}{7}$

$\frac{35y^{6}-455y^{5}+560y^{4}+6720y^{3}}{7}$

$5y^{6}-65y^{5}+80y^{4}+960y^{3}$