divide 36 in 4 parts such that if 2 is added to the first part 2 be subtracted from the second part the third multiplied by 2 and forth be divided by2 the result is equal in each case
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first part is 8, the second part is 12, the third part is 5, and the fourth part is 20. The number all four operations result in is 10.
This was a pretty basic algebra word problem. The way I learned to do it in school was like this:
First, get it in the form of unreadable henscratches. Algebra teachers love their unreadable henscratches. Representing the four parts as A, B, C, and D, we have the following
This was a pretty basic algebra word problem. The way I learned to do it in school was like this:
First, get it in the form of unreadable henscratches. Algebra teachers love their unreadable henscratches. Representing the four parts as A, B, C, and D, we have the following
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