Question

Divide 36 in two parts such that sum of their reciprocal should be 1/5​

Answer 1

Answer:

Let one part of 36 be x

So, Another part of 36 is 36-x

Now we are give that that 1/5 of one part is equal to 1/7 of the other.

A.T.Q

\frac{1}{5}x=\frac{1}{7}(36-x)

5

1

x=

7

1

(36−x)

\frac{1}{5}x=\frac{36}{7}-\frac{x}{7}

5

1

x=

7

36

−

7

x

\frac{1}{5}x+\frac{x}{7}=\frac{36}{7}

5

1

x+

7

x

=

7

36

\frac{7x+5x}{35}=\frac{36}{7}

35

7x+5x

=

7

36

\frac{12x}{35}=\frac{36}{7}

35

12x

=

7

36

x=\frac{36}{7}\times \frac{35}{12}x=

7

36

×

12

35

x=15x=15

Another part = 36 -15 = 21

Hence the one part is 15 and another part is 21.

Answer 2

Ans is 21 and 15 make sure your equations are correct