Question

Divide 36 into 4 so that if 2 is added to the first part 2 is subtracted from the second part 2 is divided by the third part and 2 is multiplied by the fourth part then the resulting number is same in each case

Answer 1

Answer:

A=6,b=10,c=4,d=16

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Step-by-step explanation:

let a,b,c,d be 4 numbers after dividing in to 4 parts.

now a+b+c+d=36

again a+2=b-2=c×2=d÷2

=>b-a=4,b=a+4

c=(a+2)/2

d=2(a+2)

now putting all these values in main eqn

a+a+4+(a+2)/2+2a+4=36

=>4a+8+(a+2)/2=36

=>9a+18=72

=>9a=54

*a=6

now b=a+4=6+4=10

again c=(a+2)/2=(6+2)/2=4

now d=2(a+2)=2(6+2)=2×8=16