Question

divide 36 into four parts so that if 2 is added to the frist part, 2 is subtracted from the second part, the third part is multiplied by 2, and the fourth part is divided by2, then the resulting number is the same in each case

Answer 1

Let a, b, c, d be the four parts.
So according to the given conditions,
2 + a = b - 2
b - 2 = 2c
2c = d/2
a + b + c + d = 36
Solving the above equations,
a = 6, b = 10, c = 4, d = 16