Question

. Divide 36 into two parts in such a way that 1/5 of one part is equal to 1/7
of the other.

Answer 1

Answer:

The one part is 15 and another part is 21.

Step-by-step explanation:

Let one part of 36 be x

So, Another part of 36 is 36-x

Now we are give that that 1/5 of one part is equal to 1/7  of the other.

A.T.Q

$\frac{1}{5}x=\frac{1}{7}(36-x)$

$\frac{1}{5}x=\frac{36}{7}-\frac{x}{7}$

$\frac{1}{5}x+\frac{x}{7}=\frac{36}{7}$

$\frac{7x+5x}{35}=\frac{36}{7}$

$\frac{12x}{35}=\frac{36}{7}$

$x=\frac{36}{7}\times \frac{35}{12}$

$x=15$

Another part = 36 -15 = 21

Hence the one part is 15 and another part is 21.

Answer 2

Answer:

$Required \: two \: parts :\\One \: part = 15\\</p><p>Other \: part =21$

Step-by-step explanation:

$Given \: number = 36$

$Let \: x \: and \: (36-x)\\are \: two \: parts$

Dividing 36 into two parts in such a way that 1/5 of one part is equal to 1/7of the other.

$\frac{x}{5}= \frac{36-x}{7}$

$\implies 7x = 5(36-x)$

$\implies 7x = 5\times 36 - 5x$

$\implies 7x+5x = 5\times 36$

$\implies 12x= 5\times 36$

$\implies x = \frac{ 5\times 36}{12}$

$\implies x = 5 \times 3$

$\implies x = 15$

Therefore,

$Required \: two \: parts :\\One \: part = x = 15\\</p><p>Other \: part = 36-x \\=36-15\\=21$

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