Question

divide 36 into two parts in such a way that 1/5 of one part is equal to 1/7 of the other

Answer 1

let the two parts be x and y
then,
x+y=36 (I)&
x/5=y/7
implies,. 7x-5y=0(ii) by cross multiplation
multiplying eq (I) by 5 and adding both equations we get,
12x= 180
x=180/12. = 15
substituting x in eq (I) we get
y=21

thus, required parts are 15 & 21...

thank u !!!

Answer 2

Answer:

let the first part be x and the second part be 36-x

according to the question

1/5 * x = 1/7 ( 36 - x)

x/5 = 36 - x/7

7 * x = 5 ( 36 - x)

7x = 180 - 5x

7x + 5x =  180

12x = 180

x = 15

first part = 15

second part = 21

Step-by-step explanation: