Question

divide 36 into two parts in such a way that 1/5 of the one part is equal to 1/7 of the other part

Answer 1

Let one part = x

other part = 36-x

Given that 1/5 of the one part is equal to 1/7 of the other part

$\Rightarrow \frac{x}{5} = \frac{36 - x}{7} \\ \\ \Rightarrow x \times 7 = (36 - x) \times 5 \\ \\ \Rightarrow 7x = 180 - 5x \\ \\ \Rightarrow 7x + 5x = 180 \\ \\ \Rightarrow 12x = 180 \\ \\ \Rightarrow x = \frac{180}{12} \\ \\ \Rightarrow x = 15 \\ \\ 36 - x = 36 - 15 = 21$

Thus two parts are 15 and 21

Answer 2

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Let one part = x

other part = 36-x

Given that 1/5 of the one part is equal to 1/7 of the other part

$\Rightarrow \frac{x}{5} = \frac{36 - x}{7} \\ \\ \Rightarrow x \times 7 = (36 - x) \times 5 \\ \\ \Rightarrow 7x = 180 - 5x \\ \\ \Rightarrow 7x + 5x = 180 \\ \\ \Rightarrow 12x = 180 \\ \\ \Rightarrow x = \frac{180}{12} \\ \\ \Rightarrow x = 15 \\ \\ 36 - x = 36 - 15 = 21$

Thus two parts are 15 and 21.

HOPE SO IT WILL HELP......