Question

divide 36 into two parts in such a way that the difference between 1 by 5 of 1 part and 1 by 7 of the other is equal to zero​

Answer 1

Answer:

let first part be x and second be 36-x

acc to ques.

x/5-(36-x)/7=0

x/5-(36/7-x/7)=0

x/5-36/7+x/7=0

x/5+x/7=36/7

(7x+5x)/35=36/7

12x=36*35/7=36*5=180

x=180/12=15

x=15, so, other number is 16

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