Divide 36 into two parts in such a way that1/5of one part Is equal to 1/7of the other
Answers
Answer:
The one part is 15 and another part is 21.
Step-by-step explanation:
Let one part of 36 be x
So, Another part of 36 is 36-x
Now we are give that that 1/5 of one part is equal to 1/7 of the other.
A.T.Q
\frac{1}{5}x=\frac{1}{7}(36-x)
5
1
x=
7
1
(36−x)
\frac{1}{5}x=\frac{36}{7}-\frac{x}{7}
5
1
x=
7
36
−
7
x
\frac{1}{5}x+\frac{x}{7}=\frac{36}{7}
5
1
x+
7
x
=
7
36
\frac{7x+5x}{35}=\frac{36}{7}
35
7x+5x
=
7
36
\frac{12x}{35}=\frac{36}{7}
35
12x
=
7
36
x=\frac{36}{7}\times \frac{35}{12}x=
7
36
×
12
35
x=15x=15
Another part = 36 -15 = 21
Hence the one part is 15 and another part is 21
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Answer:
Let first part be x.
⇒ Second part = 36 - x (as their sum is 36)
1/5 of x = x/5
1/7 of 36-x = (36 - x)/7
⇒ 7x = 5(36 - x) = 180 -5x (cross - multiplying)
⇒ 12x = 180 (adding 5x on both sides)
⇒ x = 15 (dividing both sides by 12)
⇒ 36 - 15 = 21
The two parts are 15 and 21