divide : 36a²+138ab+126b²by(2a+3b)
Answers
Answer:
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When we divide (36a²+138ab+126b²) by (2a+3b) will get 18a + 42b
Given:
36a²+138ab+126b² and 2a+3b
To find:
Divide 36a²+138ab+126b² by (2a+3b)
Solution:
Given 36a²+138ab+126b²
Factorize the above expression as given below
⇒ 36a²+138ab+126b²
take 6 as common
⇒ 6 [ 6a²+23ab+21b² ]
⇒ 6 [ 6a²+23ab+21b² ]
⇒ 6 [ 6a²+14ab + 9ab +21b² ] [ take 23ab = 14ab + 9ab ]
⇒ 6 [2a(3a + 7b) + 3b(3a + 7b) ]
⇒ 6 [ (3a + 7b) (2a + 3b) ]
36a²+138ab+126b² = 6 [ (3a + 7b) (2a + 3b)
Now divide 6 [ (3a + 7b) (2a + 3b)] by (2a+3b)
= 6 [ (3a + 7b) (2a + 3b)] / (2a+3b)
= 6(3a + 7b)
= 18a + 42b
Therefore,
When we divide (36a²+138ab+126b²) by (2a+3b) will get 18a + 42b
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