Question

Divide 3740 in three parts in such a way that half of the first part, one-third of the second part and onesixth of the third part are equal

Answer 1

let first part is x
second part is y
third part is z
then
x+y+z=3740...........(1)
& x/2=y/3=z/6
then
3x-2y=0.......(2)
& 2y=z........ .....(3)
putting the value of z in (1)
x+3y=3740.........(4)
2*(4)+3*(2)
11x=7480
or x=680
putting the value of x in (2)
then 2y=2040
or y=1020
putting the value of y in(3)
z=2040

x=680
y=1020
z=2040.............(ans)