Question

divide - 39 x to the power 4 by under root 13 x to the power 2

Answer 1

GIVEN :

Divide the expression $\frac{-39x^4}{\sqrt{13}x^2}$

TO FIND :

The simplified form of  the given expression .

SOLUTION :

Given expression is $\frac{-39x^4}{\sqrt{13}x^2}$

Solving the given expression as below :

$\frac{-39x^4}{\sqrt{13}x^2}$

$=\frac{-(3\times 13)x^4}{\sqrt{13}x^2}$

By using the rule of exponent,

$\frac{1}{a^n}=a^{-n}$

$=\frac{-(3\times 13)x^4.x^{-2}}{\sqrt{13}}$

By using quotient rule of exponent,

$\frac{a^m}{a^n}=a^{m-n}$

$=\frac{-(3\times 13)x^{4-2}}{\sqrt{13}}$

$=\frac{-(3\times 13)x^{2}}{\sqrt{13}}$

$=\frac{-3(\sqrt{13}\times \sqrt{13})x^{2}}{\sqrt{13}}$

By using the square root property :

$a=\sqrt{a}\times \sqrt{a}$

here a = 13

$=-3\sqrt{13}x^2$

⇒ $\frac{-39x^4}{\sqrt{13}x^2}=-3\sqrt{13}x^2$

∴ the simplified form for the given expression is $-3\sqrt{13}x^2$

Answer 2

Answer:

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