divide 39x³(50x²-98) by 26x²(5x+7)
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39y3 (50y2 – 98) ÷ 26y2(5y + 7)
=39y3(50y2−98)26y2(5y+7)
=39y3×2×(25y2−49)26y2(5y+7)
=39y3×2×{(5y)2−(7)2}26y2(5y+7)
=39y3×2×(5y+7)(5y−7)26y2(5y−7). . . . [Using Identity III
= 3y (5y – 7)
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