Question

divide 39y^3(50y^2-98) by 26y^2(5y+7)​

Answer 1

Answer:

$15 {y}^{2} - 21$

Step-by-step explanation:

$\frac{39 {y}^{3}(50 {y}^{2} - 98) }{26 {y}^{2} (5y + 7)}$

$= \frac{3 {y}^{3 - 2} \times 2(25 {y}^{2} - 49) }{2(5y + 7)}$

$= \frac{3y( {(5y)}^{2} - {7}^{2} ) }{(5y + 7)}$

$= \frac{3y(5y + 7)(5y - 7)}{(5y + 7)}$

$= 3y(5y - 7)$

$= 15 {y}^{2} - 21$