Math, asked by srishtibouri, 1 month ago

Divide √3a^4+2a^3-6a by 3a

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Answered by nageshgupt

Answer:

We have, (√3a4 + 2√3a3 + 3a2 – 6a) / 3a √3a4/3a + 2√3a3/3a + 3a2/3a – 6a/3a By using the formula an / am = an-m √3/3 a4-1 + 2√3/3 a3-1 + a2-1 – 2a1-1 1/√3 a3 + 2/√3 a2 + a – 2

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Divide √3a^4+2a^3-6a by 3a​

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Divide √3a^4+2a^3-6a by 3a