Question

Divide 3p2 + 6p + 2 by 3p2. = = B + C +

Answer 1

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Answer 2

Answer:

The require result is $B+C+..=\frac{2}{p}+\frac{2}{3p^2}+1$

Step-by-step explanation:

Given : Polynomial $3p^2+6p+2$ divided by $3p^2$

To find : B + C + ..

Solution :

When we divide polynomial $3p^2+6p+2$ by $3p^2$

we get,

$=\frac{3p^2+6p+2}{3p^2}$

$=\frac{3p^2}{3p^2}+\frac{6p}{3p^2}+\frac{2}{3p^2}$

$=1+\frac{2}{p}+\frac{2}{3p^2}$

Comparing with B+C+..

$B=\frac{2}{p}\\C=\frac{2}{3p^2}\\..= 1$

The require result is $B+C+..=\frac{2}{p}+\frac{2}{3p^2}+1$