Math, asked by kkhushi27, 10 months ago

divide 3pqr+6p2 qr2-9p p3 q2 r3 by -3pqr

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Answered by shaktivelcleanway

Answer:

Ltd. ... 8 = p3 – 6p2 + 12 ⇒ p3 – 6p2 + 12p – 8 = 0 ... (CDS 2007) (a) qx2 – px + 1 = 0 (b) q2 + px + 1 = 0 9. ... ( pqr ) 3 ⇒ ( p + q + r ... please follow

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divide 3pqr+6p2 qr2-9p p3 q2 r3 by -3pqr​

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divide 3pqr+6p2 qr2-9p p3 q2 r3 by -3pqr