Math, asked by sukantmishra32, 1 year ago

Divide 3x^2+5x-1 by (x+2) and verify the division algorithm

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Answered by shivam5411
73
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Answered by ashishks1912
39

Given that Divide 3x^2+5x-1 by (x+2)

TO VERIFY :

The division algorithm for the given polynomial.

SOLUTION :

First divide the given polynomial

          3x-1

      _________________

x+2) 3x^2+5x-1

       3x^2+6x

__(-)___(-)________

               -x-1

               -x-2

    ____(+)_(+)______

                   1

            _________

Therefore the quotient is 3x-1 and remainder is 1

Now verify the division algorithm :

Dividend =quotient\times divisor + remainder

3x^2+5x-1=(3x-1)\times (x+2)+1

By using Distributive property :

(x+y)(a+b)=x(a+b)+y(a+b)

3x^2+5x-1=(3x)(x+2)-1(x+2)+1

By using Distributive property :

a(x+y)=ax+ay

3x^2+5x-1=3x(x)+3x(2)-1(x)-1(2)+1

3x^2+5x-1=3x^2+6x-x-2+1

Adding the like terms

3x^2+5x-1=3x^2+5x-1

Hence the Division Algorithm is  verified

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