Question

divide : (3x^2+5x+9)/(x+3)​

Answer 1

Answer:

(3x-4)+(21÷x+3)

Step-by-step explanation:

$x + 3)3 {x}^{2} + 5x + 9(3x \\ \: \: \: \: \: \: \: \: \: \: \: \: 3 {x}^{2}+ 9x \\ \ x + 3) - 4x + 9( - 4 \\ \: \: \: \: \: \: \: \: \: \: \: \: - 4x - 12 \\ = > ( x + 3)(3x - 4) + 21 = 3 {x}^{2} + 5x + 9 \\ therefore \: (3 {x }^{2} + 5x + 9 \div x + 3) = 3x - 4 + (21 \div x + 3)$