Math, asked by abelmartin3060, 4 months ago

divide 3x^3-4x^2+5x by 2x

Answers

Answered by abhishekshibu9267

0

Answer:

(3x^2-4x +5)/2

Step-by-step explanation:

(3x^3-4x^2+5x)/2x

x(3x^2-4x +5)/2x

(3x^2-4x +5)/2

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