Question

divide 3X^4-4X^2+8X-1 by X-2

Answer 1

Answer:

3x^4-4x^2+8x-1÷x-2

x-2=0

x=2

p(x)=3x^4-4x^2+8x-1

p(2)=3(2)^4-4(2)^2+8(2)-1

=3(16)-4(4)+16-1

=48-16+16-1

=47

Remainder=47

Step-by-step explanation:

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