Question

Divide 3x square +x-1 by x+1

Answer 1

Step-by-step explanation:

here is your solution

hope it helps you

Answer 2

Quotient of division : 3x-2,

Remainder of division : 1

Given:

• $3 {x}^{2} + x - 1$ and
• $x + 1$

To find:

• Division of first polynomial by later.

Solution:

Step 1:

Write the polynomial for division.

$x + 1 \: ) \: 3 {x}^{2} + x - 1 \: ($

Step 2:

Multiply (x+1) by 3x.

$x + 1 \: ) \: 3 {x}^{2} + x - 1 \: ( \: 3x \\ 3 {x}^{2} + 3x \\ ( - ) \: \: \: ( - ) \: \: \: \\ - - - - - \\ - 2x - 1$

Step 3:

Multiply (x+1) by -2.

$x + 1 \: ) \: 3 {x}^{2} + x - 1 \: ( \: 3x - 2\\ 3 {x}^{2} + 3x \\ ( - ) \: \: \: ( - ) \: \: \: \\ - - - - - \\ - 2x - 1 \\ - 2x - 2 \\ ( + ) \: \: ( + ) \\ - - - - - \\ 1 \\ - - - - -$

Thus,

Quotient of division : 3x-2 and remainder of division: 1

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