Question

Divide 3x²-2x-40 by 3x+10
Plz send the answer as fast as you can

Answer 1

the answer is given in the attachment above and please pardon my handwriting

Answer 2

Answer:

By dividing $3x^{2} -2x-40$ by $3x+10$ we get $x-4$

Step-by-step explanation:

Let the given polynomials be

$f(x)=3x^{2} -2x-40\\g(x)=3x+10$

Before dividing the polynomial f(x) we shall factorize it for our convenience

$f(x)=3x^{2} -2x-40=3x^{2} -12x+10x-40\\=3x(x-4)+10(x-4)=(3x+10)(x-4)$

On division of the polynomial f(x) with g(x) we get

$\frac{(3x+10)(x-4)}{3x+10} =x-4$

By dividing $3x^{2} -2x-40$ by $3x+10$ we get $x-4$

#SPJ2