Math, asked by adhru, 30 days ago

divide 3x² -x ³ - 32x + 5 by x -1 - x² and verify the division algorithm
please answer as soon as possible urgent

Answers

Answered by ItzShubham95
0

Answer:

\green{\bigstar}\underline{\underline{\textsf{\textbf{ Given\::- }}}}

Vertices of triangle = (0,5) , (8,0) and (2,0).

\green{\bigstar}\underline{\underline{\textsf{\textbf{ To\:Find\::- }}}}

Area of triangle = ?

\green{\bigstar}\underline{\underline{\textsf{\textbf{ Step\:by\:step\:explanation\::- }}}}

To find area of triangle, using formula of area of triangle, i.e, \blue{\bigstar}\tiny{\underline{\boxed{\bf{\orange{\dfrac{1}{2}|x_{1}(y_{2} - y_{3}) + x_{2}(y_{3} - y_{1}) + x_{3}(y_{1} - y_{2})|\:}}}}}

ㅤㅤㅤㅤㅤㅤ━━━━━━━━━━

\green{\bigstar}\underline{\underline{\textsf{\textbf{ Known\:values }}}}\begin{cases} & \sf{x_{1} = \bf{0}\:,\:\sf{y_{1}} = \bf{5}} \\ \\ & \sf{x_{2} = \bf{8}\:,\:\sf{y_{2}} = \bf{0}} \\ \\ & \sf{x_{3} = \bf{2}\:,\:\sf{y_{3}} = \bf{0}} \end{cases}

\green{\bigstar}\underline{\underline{\textsf{\textbf{ Putting\:all\:known\:values\::- }}}}

\dashrightarrow\qquad\sf Area_{(triangle)} = \dfrac{1}{2}|0(0 - 0) + 8(0 - 5) + 2(5 - 0)|

\dashrightarrow\qquad\sf Area_{(triangle)} = \dfrac{1}{2}|0(0) + 8(-5) + 2(5)|

\dashrightarrow\qquad\sf Area_{(triangle)} = \dfrac{1}{2}|0 + (-40) + 10|

\dashrightarrow\qquad\sf Area_{(triangle)} = \dfrac{1}{2}|-40 + 10|

\dashrightarrow\qquad\sf Area_{(triangle)} = \dfrac{1}{2}|-30|

\dashrightarrow\qquad\sf Area_{(triangle)} = \dfrac{1}{2}\:\times\:30

[tex]\dashrightarrow\qquad\sf Area_{(tria

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