Question

Divide 3x3+16x2+20x+8 by x-1​

Answer 1

$\frac{3 {x}^{3} + 16 {x}^{2} + 20x + 8}{x - 1 } \\ \\ = 3 {x}^{2} + 19x + 29 + \frac{37}{x - 1}$

I.e.

$(x - 1)(3 {x}^{2} + 19x + 29) + 37 = 3 {x}^{3} + 16 {x}^{2} + 20x + 8$

hope it helps