Math, asked by pratham125, 1 year ago

divide 3x³+4x²-11x+30 by 3x+10

Answers

Answered by Anonymous

HI FRIEND, HERE'S THE REQUIRED ANSWER :-
VERIFICATION :
WE KNOW THAT DIVIDEND=DIVISOR×QUOTIENT +REMAINDER.
SO APPLY THE FOLLOWING EXPRESSION IN THE FORMULA.
LHS:- 3x³+4x²-11x+30
RHS:- (x²-6x+16)(3x+10)+x-130= 3x³-18x²+48x+10x²-60x+160x+x-130=3x³+4x²-11x+30. 'verified'
Hope this helps you..
PLEASE MARK AS BRAINLIEST ANSWER!!!

Attachments:

pratham125: thanx trinity i need a help again i need verification of this answer.

Anonymous: My pleasure!!

Anonymous: Ask question again

pratham125: i need verification of this answer.

Anonymous: ok

mohan24680: can I know how you got quotient

pratham125: i can't put up the values in this formula p(x) = g(x)*q(x)*r(x)

pratham125: this is the verification formula

mohan24680: can anyone answer my question which I have mentioned above

Answered by mohan24680

The zero of 3x+10 is - 10 /3
F(-10 /3) =3(10 /3)3 +4(10/3) 2-11(10/3)+30
1027 /3 +112/3 +22/3-43/3+30
1027/3 +112/3 +22/3 - 43/3+90/3
1251/3 - 43/3
1208/3

pratham125: thanx for ur answer mohan but this not the answer.But thanx for ur help

mohan24680: I have a doubt on the above answer

mohan24680: once verify it

pratham125: ok

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