Question

Divide 3xsquare-xcube-3x+5 by x-1-xsquare. Find the remainder ​

Answer 1

➪︎ Here the remainder is 3

➪︎ Quotient is x - 2

✰︎ I hope you like it.....

Answer 2

Given:-

p(x)=0

→-x³+3x²-3x+5

→g(x)→-x²+x-1

$\rule{200}{1}$

To find:-

The remainder→r(x)?

$\rule{200}{1}$

Proof:-

•Using the Formula•

→p(x)=q(x)×g(x)+r(x)

→$\frac{p(x)}{g(x)}$=q(x)+r(x)

•Putting the Values•

→$\frac{-x^{3}+3x^{2}-3x+5}{-x^{2}+x-1}$=q(x)+r(x)

→$\frac{\cancel{-x^{3}+3x^{2}-3x+5}{-x^{2}+x-1}}{\cancel{-x^{2}+x-1}}$=q(x)+r(x)

•Refer Attachment for Division•

→q(x)=x-2

→r(x)=3

$\rule{200}{2}$