Question

divide 3y^3-1y^2-8y-8 by 4y-8

Answer 1

Answer:

$3y {}^{3} - 1y {}^{2} - 8y - 8 \div 4y - 8 \\ taking \: like \: terms \\ 3y {}^{3} - 1y {}^{2} - 8y \div 4y - 8 - 8 \\ 2y {}^{1} - 2y - 16$

hope this will help u