Question

Divide 3y4–4y3-3y-1 by y–1 to get its quotient and remainder​

Answer 1

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Answer 2

Therefore the Quotient is '3y³ + y² + y + 4' and Remainder is '-5' when the given function 3y⁴ - 4y³ - 3y -1 is divided by y-1.

Given:

Dividend = 3y⁴ - 4y³ - 3y -1

Divisor = y - 1

To Find:

The quotient and the remainder when ( 3y⁴ - 4y³ - 3y -1 ) is divided by ( y-1 ).

Solution:

The given question can be solved as shown below:

Given that,

Dividend = 3y⁴ - 4y³ - 3y -1

Divisor = y - 1

by using the synthetic division method,

y - 1 ) 3y⁴ - 4y³ - 3y -1 ( 3y³ + y² + y + 4

        3y⁴ - 3y³

____(-)__(-)____________

         0    -  y³ + 0

                   y³ - y²

________(+)__(+)________

                   0  - y² - 3y

                          y² - y

___________(+)__(+)______

                          0  -4y - 1

                               4y - 4

______________(+)__(+)____

                               0   - 5

Quotient = 3y³ + y² + y + 4

Remainder = -5

Therefore the Quotient is '3y³ + y² + y + 4' and Remainder is '-5' when the given function 3y⁴ - 4y³ - 3y -1 is divided by y-1.

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