Math, asked by karan22556, 6 months ago

Divide 3y4 - 8y3 - y2 - 5y - 5 by (y - 3). find quotient and remainder​

Answers

Answered by Anonymous
35

Answer:

Correct Question:-

Divide 3y {}^{4}  - 8y {}^{3}  -  {y}^{2}  - 5y - 5by (y – 3). Find Quotient and remainder.

Solution:-

Quotient = 3y {}^{3}  + y {}^{2}  + 2y

Remainder = – 2

See the above attachment for explanation..

Attachments:
Answered by anjalisingh159
4

Answer:

y-3) 3y⁴ - 8y³ - y² - 5y -5( 3y³+ y²+ 2y + 1

3y⁴ -9y³

- +

________

y³-y²

y³-3y²

- +

_________

2y² - 5y

2y² - 6y

- +

_________

y - 5

y - 3

- +

_______

-2

Hence, Quotient is 3y³+y²+2y+1 and remainder is -2

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