Question

Divide 3y5v+6y4 + 6y3 + 7y2 + 8y + 9 by 3y3 + 1​

Answer 1

GIVEN:

• Divisor = 3y³ +1

• Dividend = 3y^5 + 6y⁴ + 6y³ + 7y² + 8y +9

TO FIND:

• Quotient and Remainder

SOLUTION:

$\begin{array}{c|ccccccc}& {y}^{2} + 2y + 2\\\cline{2-7}3y {}^{3} + 1&3 {y}^{5} &+6 {y}^{4} &6 {y}^{3} & + 7 {y}^{2} &+ 8y& + 9\\ &3 {y}^{5} && &+y^2 \\ &-&&&-\\\cline{2-8} & & + 6 {y}^{4} & + 6 {y}^{3} & + 6 {y}^{2} & + 8y &+ 9\\&&6y^4&& &+ 2y\\ && - &&& - \\\cline{2-8} &&&6 {y}^{3} & + 6 {y}^{2} & + 6y&& + 9 \\&&&6 {y}^{ 3} & &&&+ 2\\ &&&-&&&-\\\cline{2-8}&&&& 6 {y}^{2}&+ 6y& + 7 \\\end{array}$

Hence we found,

Quotient = y² + 2y +2

Remainder = 6y² + 6y +7

Answer 2

Step-by-step explanation:

Quotient : y²+2y+2

Remainder : 6y²+6y+7