Question

Divide 3z(5z2 – 80)( z + 3) by 5z(z + 4)(z2 – z - 12)​

Answer 1

z(5z²-80) ÷ 5z(z+4) = z-4 -

Step-by-step explanation:

Given: z(5z²-80) ÷ 5z(z+4) -

Calculation:

First we factor numerator z(5z²-80)

Take out 5 from 5z²-80 and we get 5z(z²-16)

Now we factor 16 = 4²

5z(z²-4²)

Using formula, (a²-b²)=(a+b)(a-b) 5z(z²-4²)→ 5z(z+4)(z-4)

Simplified fraction

5z(z+4)(z-4) 5z(z+4)

Cancel like factor from numerator and denominator

⇒ Z-4

Thus, z(5z²-80) ÷ 5z(z+4) = z-4