divide 4 a2 b2 c by 9 a2 c
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Answer:
a+b+c=9 and a2+b2+c2=35
Using formula,
(a+b+c)2=a2+b2+c2+2(ab+bc+ca)
92=35+2(ab+bc+ca)
2(ab+bc+ca)=81−35=46
(ab+bc+ca)=23
using formula,
(a3+b3+c3)−3abc=(a2+b2+c2−ab−bc−ca)(a+b+c)
a3+b3+c3−3abc=(35−23)×9=9×12=108
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