Question

Divide 4( x²yz + xy² z+xyz²) by 8xyz.

Answer 1

Step-by-step explanation:

Take xyz common from the numerator.

=>

$4(xyz)(x + y + z) \div 8xyz$

Now, xyz gets cancel out and 4/8 = 1/2, therefore the answer is:

$\frac{x + y + z}{2}$

Answer 2

$\blue{\mathfrak{\underline{\huge{Answer}}}:} \\ \\ \frac{4( {x}^{2}yz + x {y}^{2}z + xy {z}^{2} ) }{8xyz} \\ \blue{\underline{\large{Take \: xyz \: common \: from \: numerator}}:} \\ = \frac{4xyz( x+ y+ z ) }{8xyz} \\ = \frac{x + y + z}{2} \\ \\ \red{\mathfrak{\underline{\large{Hope \: It \: Helps \: You }}}} \\ \blue{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}$