Question

divide 40 in to two parts such that sum of their reciprocal is 8/75​

Answer 1

Answer:

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Answer 2

Let the numbers be a and b

a+b=40

∴a=40−b

Sum of their reciprocals is

75

8

a

1

+

b

1

=

75

8

ab

a+b

=

75

8

ab=

8

75×40

=375

b(40−b)=375

b

2

−40b+375=0

b

2

−25b−15b+375=0

b=15,25

Hence, the two numbers are 15 and 25.