divide 40 into two parts such that 1/4 of one part is 3/8 of the other
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Hey here is your answer
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let, the first part be x
and the second part be y
then ,
1/4 x = 3/8 y
x = 3/2 y ....... (1)
Now ,
x + y = 40
3/2 y + y = 40
........putting the value of x from equation 1
(3y + 2y ) / 2 = 40
5y = 40 × 2
y = 80 / 5
y = 16
Now from equation 1 .
x = 3/2 y
x = 3/2 × 16
x = 3 × 8
x = 24
________________________
Hope it may helpful to you
plzzz mark me as brianlist
@ajaman.......
_____________________
let, the first part be x
and the second part be y
then ,
1/4 x = 3/8 y
x = 3/2 y ....... (1)
Now ,
x + y = 40
3/2 y + y = 40
........putting the value of x from equation 1
(3y + 2y ) / 2 = 40
5y = 40 × 2
y = 80 / 5
y = 16
Now from equation 1 .
x = 3/2 y
x = 3/2 × 16
x = 3 × 8
x = 24
________________________
Hope it may helpful to you
plzzz mark me as brianlist
@ajaman.......
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