Question

Divide 40 into two parts such that 1/4 of one part is equal to 3/8 of the other
​

Answer 1

Answer:

The two numbers are 16 and 24

Step-by-step explanation:

Let the two numbers be x and y.

Therefore, x + y = 40

Given 1/4 of one number is 3/8 of other number.

$\frac{x}{4} = \frac{3y}{8}$

$x = \frac{3y}{2}$

The following condition has to be satisfied

$x + y = 40$

$\frac{3y}{2} + y = 40$

$\frac{3y + 2y}{2} = 40$

$5y = 40 \times 2$

$y = \frac{80}{5}$

$y = 16$

Plug in the value of y in the following equation

$x = \frac{3y}{2} = \frac{3 \times 16}{2} = 24$

Mark it as Brainliest.