Question

Divide 40 into two parts such that 1/4th of one part is 3/8th of the other. try to answer as fast as you can

Answer 1

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Answer 2

Hey Pretty Stranger!

Let the first part be x and second part be (40 - x)

From the given condition :

$\longrightarrow \sf \: x \times \dfrac{1}{4} = \dfrac{3}{8} (40 - x)$

$\longrightarrow \sf \: 2x = 3(40 - x)$

$\longrightarrow \sf \: 2x =120 - 3x$

$\longrightarrow \sf \: 2x + 3x = 120$

$\longrightarrow \sf \: 5x = 120$

$\longrightarrow \sf \: x = \cancel \dfrac{120}{5}$

$\longrightarrow \sf \: \large \boxed{ \sf \: x = 24}$

$\therefore$ First part is 24 and second part is (40 - 24) = 16.