divide 40 into two parts such that one fourth of one part is three eight of the other
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6
Let the first part be a and second part be b
a/4 = 3b/8
=> 8a =12b
=> 2a = 3b
=> a = 3b/2
Now,
a+b = 40
=> b+3b/2 = 40
=> 5b/2 = 40
=> b = 16
First part = 24
Second part = 16
a/4 = 3b/8
=> 8a =12b
=> 2a = 3b
=> a = 3b/2
Now,
a+b = 40
=> b+3b/2 = 40
=> 5b/2 = 40
=> b = 16
First part = 24
Second part = 16
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3
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