Divide 40 into two parts such that one part is 10 more than the other.
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let 1st part = x
2nd part = x + 10
ATQ
x + x +10 = 40
2x +10 =40
2x = 40 -10 = 30
x = 30/ 2
x = 15
so is part = 15
2nd part = 15 + 10 = 25
2nd part = x + 10
ATQ
x + x +10 = 40
2x +10 =40
2x = 40 -10 = 30
x = 30/ 2
x = 15
so is part = 15
2nd part = 15 + 10 = 25
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