Math, asked by momulaveeresham9866, 4 months ago

Divide 400 into two parts such that one third of the first part is 40less than the other. Then, the smallest part is

Answers

Answered by lathpiyush
1

Answer: 130

Step-by-step explanation: first part is 130 and the second part is 270

Answered by udayagrawal49
1

Answer:

The smallest part is 130.

Step-by-step explanation:

We have to divide 400 into two parts.

Let one part be x and another part be y.

According to question, one third of first part is 40 less than the other.

⇒ x/3 = y-40

⇒ x = 3y - 120            -------[1]

Also, x+y = 400

⇒ 3y-120+y = 400

⇒ 4y - 120 = 400

⇒ 4y = 400+120 = 520

⇒ y = 520/4 = 130

And, x = 3y-120 = 3(130) - 120 = 390-120

⇒ x = 270

So, the smallest part is 130.

Please mark it as Brainliest.

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