Question

Divide 400into two parts such that 1/3 of the first part is 40 less than the other.

Answer 1

Let the first part be x and the second part be y.
Hence, 1/3x = y-40
And, y= 1/3x + 40
Therefore, (1/3x + 40)+ x = 400
1/3x + x = 360
4/3x = 360
x = 360* 3/4
x = 270 ( first part )
y = 1/3x + 40 = 130

Answer 2

Answer: 270 and 130.

Step-by-step explanation:

Let the first part be x and the second part be y.

Hence, 1/3x = y-40

y= 1/3x + 40

and

x+y =400

(1/3x + 40)+ x = 400

1/3x + x = 360

4/3x = 360

x = 360* 3/4

x = 270

y = 1/3x + 40 = 130

so two part of 400 are 270 and 130.