divide 41 into two numbers such that the sum of the squares of the two numbers is equal to 881
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Answer:
25, 16
Step-by-step explanation:
Let the two numbers be x and y
x+y = 41
squaring both sides
(x+y)² = 41²
x² + y² + 2xy = 1681. (1)
also it is given that x² + y² = 881
putting this value in (1)
881 + 2xy = 1681
xy = 400
now
(x-y)² = x²+y²-2xy = 881 - 2×400 = 81
x-y = 9
x+y = 41
Add
2x = 50
x = 25
y = 25-9 = 16
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