Question

Divide 42(a^4 - 13a^3 + 36a^2) by 7a ( a - 4)

Answer 1

$\textbf{Given:}$

$\displaystyle\frac{42(a^4-13a^3+36a^2)}{7a(a-4)}$

$\text{Taking a^2 as common}$

$=\displaystyle\frac{42a^2(a^2-13a+36)}{7a(a-4)}$

$=\displaystyle\frac{6a(a^2-13a+36)}{a-4}$

$\text{Factorizing,}$

$=\displaystyle\frac{6a(a^2-9a-4a+36)}{a-4}$

$=\displaystyle\frac{6a(a(a-9)-4(a-9))}{a-4}$

$=\displaystyle\frac{6a(a-9)(a-4)}{a-4}$

$=6a(a-9)$

$\therefore\bf\displaystyle\frac{42(a^4-13a^3+36a^2)}{7a(a-4)}=6a(a-9)$

Find more:

4x3 – 2x2 – 3 is divided by 2x2 – 1​

https://brainly.in/question/15040570

Answer 2

Refer The Attachment ⬆️

$\green{\sf{@MrMonarque}}$

Hope It Helps You ✌️