Question

Divide 42 into two parts such that one-third of one part is equal to one-fourth of the other part.find the two numbers.

Answer 1

Answer:

The 2 numbers are 18 and 24 .

Step-by-step explanation:

By I variable :-

let the one part be x and other be 42 - x.

As we have given in the question that the both parts sums 42.

So, we got equation = x/3 = (42-x)1/4

solution -

x/3 = (42-x)1/4

⇒ x/3 = 42-x/4

⇒ 4x = 126 - 3x

⇒7x = 126

⇒ x = 18

y = 42 - 18 = 24

By II variables -

let the no. be x and y.

x + y = 42 __(i)

we have given that 1/3 of first part = 1/4 of other part.

so,

x/3 = y/4 __(ii)

Than y = 4x/3 __(iii)

Solution -

firstly we substitute the value of eq(iii) in eq (i)

⇒ x + y = 42

⇒ x + 4x/3 = 42

⇒ 7x /3 = 42

⇒ x = 42 * 3/7

⇒ x = 18

than y = 42 - 18 = 24.

Verification :

x/3 = y/4

18/3 = 24/4

6 = 6