Question

Divide 42 into two parts such that one-third of one
part is equal to one-fourth of the other part. Find the
two numbers.​

Answer 1

Answer:

Let the parts be x and y

x + y = 42

x = 42 - y

Now it is given that,

x/3 = y/4

4x = 3y

4x - 3y = 0

4(42 - y) - 3y = 0

168 - 4y - 3y = 0

168 - 7y = 0

7y = 168

y = 168/7

y = 24

x = 42 - y = 42 - 24 = 18

Therefore the parts are x = 18 and y = 24

Verification :-

18/3 = 6

24/4 = 6

One third of one part = one fourth of the other part

6 = 6

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Answer 2

Answer:

1 21

2 21

PLEASE MARK BRAINLIEST